CH_3-CO-CH_2-COOH xrightarrow{Delta} X xright | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $\beta$-keto acids undergo decarboxylation on heating to give ketones.$CH_3-CO-CH_2-COOH \xrightarrow{\Delta} CH_3-CO-CH_3 + CO_2$Here,the product

Vedclass · Accepted Answer

Vedclass · Answer

(A) $\beta$-keto acids undergo decarboxylation on heating to give ketones.$CH_3-CO-CH_2-COOH \xrightarrow{\Delta} CH_3-CO-CH_3 + CO_2$Here,the product $X$ is acetone $(CH_3-CO-CH_3)$.Acetone reacts with $HCN$ in the presence of a base $(OH^-)$ to form acetone cyanohydrin $(Y)$.$CH_3-CO-CH_3 + HCN \xrightarrow{OH^-} CH_3-C(OH)(CN)-CH_3$The structure of acetone cyanohydrin is shown in option $A$.

$CH_3-CO-CH_2-COOH$ $\xrightarrow{\Delta} X$ $\xrightarrow[OH^-]{HCN} Y$,$Y$ is:

Similar Questions

Paraldehyde is

Product $C$ is

Which of the following on reaction with conc. $NaOH$ gives an alcohol?

Arrange the following compounds in increasing order of their equilibrium constants for hydration:
$(A). CH_3COCH_3, (B). CH_3CHO, (C). ClCH_2COCH_3, (D). HCHO, (E). ClCH_2CHO$

Which of the following compounds on reaction with ammoniacal silver nitrate solution forms a precipitate of silver?

Vedclass Test Series

Exam Paper Generator

Online Exam Module