Which of the following is the correct order o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Electronegativity generally increases across a period from left to right and decreases down a group.For the given elements: $Si$ (Group $14$,Perio

Vedclass · Accepted Answer

$Si < P < C < N$

Vedclass · Answer

(C) Electronegativity generally increases across a period from left to right and decreases down a group.For the given elements: $Si$ (Group $14$,Period $3$),$P$ (Group $15$,Period $3$),$C$ (Group $14$,Period $2$),and $N$ (Group $15$,Period $2$).Comparing their values on the Pauling scale: $Si \approx 1.90$,$P \approx 2.19$,$C \approx 2.55$,and $N \approx 3.04$.Therefore,the correct order of increasing electronegativity is $Si < P < C < N$.

Which of the following is the correct order of electronegativity?

Similar Questions

The correct order of electronegativity of group $13$ elements is

Fluorine is a better oxidising agent than $Br_{2}$. It is due to

Among the following,the pairs of elements having approximately the same electronegativity values are:
$I$. $H$ and $P$
$II$. $Be$ and $Al$
$III$. $N$ and $Cl$
$IV$. $C$ and $P$

Electronic configuration of four elements $A, B, C$ and $D$ are given below $:$
$(A) 1s^2 2s^2 2p^3$
$(B) 1s^2 2s^2 2p^4$
$(C) 1s^2 2s^2 2p^5$
$(D) 1s^2 2s^2 2p^2$
Which of the following is the correct order of increasing electronegativity $(Pauling's scale)$?

How would you react to the statement that the electronegativity of $N$ on Pauling scale is $3.0$ in all the nitrogen compounds?

Vedclass Test Series

Exam Paper Generator

Online Exam Module