The atomic radii of F and Ne in mathring{A} u | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The atomic radius generally decreases across a period from left to right due to an increase in effective nuclear charge. $F$ (Fluorine) is a halog

Vedclass · Accepted Answer

$0.72, 1.60$

Vedclass · Answer

(A) The atomic radius generally decreases across a period from left to right due to an increase in effective nuclear charge. $F$ (Fluorine) is a halogen with atomic number $9$,and $Ne$ (Neon) is a noble gas with atomic number $10$. For noble gases,the atomic radius is defined as the van der Waals radius,which is significantly larger than the covalent radius of other elements in the same period. The covalent radius of $F$ is approximately $0.72 \ \mathring{A}$. The van der Waals radius of $Ne$ is approximately $1.60 \ \mathring{A}$. Therefore,the values are $0.72 \ \mathring{A}$ and $1.60 \ \mathring{A}$ respectively.

The atomic radii of $F$ and $Ne$ in $\mathring{A}$ units are respectively .......

Similar Questions

The atomic radii of the elements across the second period of the periodic table:

For which of the following ionic species would the radius be maximum?

In which periods are $Na$ and $F$ located? What is the order of their atomic radii and why?

Identify the isoelectronic species from the following groups.

The single bond covalent radius $(SBCR)$ of $P$ is $0.11 \ nm$. The single bond covalent radius of $Cl$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module