The angle between two hybrid orbitals is 105^ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The relationship between the bond angle $(	heta)$ and the $s-$character $(s)$ in hybrid orbitals is given by the formula: $\cos 	heta = \frac{s}

Vedclass · Accepted Answer

$22 - 23 \%$

Vedclass · Answer

(C) The relationship between the bond angle $(	heta)$ and the $s-$character $(s)$ in hybrid orbitals is given by the formula: $\cos 	heta = \frac{s}{s-1}$.Given $	heta = 105^o$,we have $\cos(105^o) = -0.2588$.Substituting this into the equation: $-0.2588 = \frac{s}{s-1}$.$-0.2588(s-1) = s$.$-0.2588s + 0.2588 = s$.$1.2588s = 0.2588$.$s = \frac{0.2588}{1.2588} \approx 0.2056$.Converting to percentage,$s \approx 20.56 \%$.Among the given options,the value closest to this result is $22 - 23 \%$.

The angle between two hybrid orbitals is $105^o$. The $s-$character of the hybrid orbitals will be ..............

Similar Questions

Explain the geometry of $SF_{6}$.

The hybridisation of xenon atom in $XeF_4$ is

In $HCHO$,the carbon atom has which hybridization?

The hybridization states of the chlorine atom in $ClO_4^-$,$ClO_3^-$,and $ClO_2^-$ are respectively .....

Which of the following shows a linear structure?

Vedclass Test Series

Exam Paper Generator

Online Exam Module