How many millimoles of H^{+} ions are present | vedclass

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(C) The normality $(N)$ of a solution is given by $N = M 	imes 	ext{n-factor}$.For $H_3PO_4$,the n-factor is $3$ (as it is a tribasic acid).Therefor

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$60$

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(C) The normality $(N)$ of a solution is given by $N = M 	imes 	ext{n-factor}$.For $H_3PO_4$,the n-factor is $3$ (as it is a tribasic acid).Therefore,the molarity $(M)$ is $M = \frac{N}{3} = \frac{0.6}{3} = 0.2 \, M$.Millimoles of $H_3PO_4 = 	ext{Molarity} 	imes 	ext{Volume in } mL = 0.2 	imes 100 = 20 \, mmol$.Since $1 \, mol$ of $H_3PO_4$ dissociates to give $3 \, mol$ of $H^{+}$ ions,$1 \, mmol$ of $H_3PO_4$ gives $3 \, mmol$ of $H^{+}$ ions.Millimoles of $H^{+} = 3 	imes 20 = 60 \, mmol$.

How many millimoles of $H^{+}$ ions are present in $100 \, mL$ of $0.6 \, N \, H_3PO_4$?

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