How many grams of ethanol must be added to 1. | vedclass

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Question

(C) Let $W$ be the mass of ethanol in grams. The molar mass of ethanol $(C_2H_5OH)$ is $46 \ g/mol$. Moles of ethanol = $\frac{W}{46}$. Moles of water

Vedclass · Accepted Answer

$638.89$

Vedclass · Answer

(C) Let $W$ be the mass of ethanol in grams. The molar mass of ethanol $(C_2H_5OH)$ is $46 \ g/mol$. Moles of ethanol = $\frac{W}{46}$. Moles of water = $\frac{1000 \ g}{18 \ g/mol} = 55.56 \ mol$. Mole fraction of ethanol $(x_{ethanol})$ = $\frac{n_{ethanol}}{n_{ethanol} + n_{water}} = 0.2$. $\frac{W/46}{W/46 + 55.56} = 0.2$. $W/46 = 0.2 	imes (W/46 + 55.56)$. $W/46 = 0.2(W/46) + 11.112$. $0.8(W/46) = 11.112$. $W/46 = 13.89$. $W = 13.89 	imes 46 = 638.94 \ g$. Rounding to the nearest option,the mass is $638.89 \ g$.

How many grams of ethanol must be added to $1.0 \ kg$ of water to have a mole fraction of ethanol equal to $0.2$?

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