68 , ^circ F = ........ , K. | vedclass

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Question

(C) The relationship between Fahrenheit and Celsius is given by: $^\circ F = \frac{9}{5} ( ^\circ C ) + 32$. Substituting $68 \, ^\circ F$: $68 = \fra

Vedclass · Accepted Answer

$293$

Vedclass · Answer

(C) The relationship between Fahrenheit and Celsius is given by: $^\circ F = \frac{9}{5} ( ^\circ C ) + 32$. Substituting $68 \, ^\circ F$: $68 = \frac{9}{5} ( ^\circ C ) + 32$. $68 - 32 = \frac{9}{5} ( ^\circ C ) \implies 36 = \frac{9}{5} ( ^\circ C )$. $^\circ C = \frac{36 	imes 5}{9} = 20 \, ^\circ C$. To convert Celsius to Kelvin: $K = ^\circ C + 273.15$. $K = 20 + 273 = 293 \, K$ (using $273$ as the standard conversion factor).

$68 \, ^\circ F = ........ \, K.$

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