$0.15 \, \mathring{A} = \dots \, \text{nm}$
- A$1.5$
- B$0.15$
- C$15$
- D$0.015$
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Similar Questions
Match the units in Column-$A$ with their equivalent values in Column-$B$ and select the correct option:
Column-$A$
Column-$B$
$1$. Femtometer
$(P)$. $10^{-3} \ \mu m$
$2$. Picometer
$(Q)$. $10^{-3} \ mm$
$3$. Nanometer
$(R)$. $10^{-3} \ pm$
$4$. Micrometer
$(S)$. $10^{-3} \ cm$
$(W)$. $10^{-3} \ nm$
| Column-$A$ | Column-$B$ |
| $1$. Femtometer | $(P)$. $10^{-3} \ \mu m$ |
| $2$. Picometer | $(Q)$. $10^{-3} \ mm$ |
| $3$. Nanometer | $(R)$. $10^{-3} \ pm$ |
| $4$. Micrometer | $(S)$. $10^{-3} \ cm$ |
| $(W)$. $10^{-3} \ nm$ |
Easy
View SolutionObserve the following:
$I) 0.0063$
$II) 132.00$
$III) 1004$
The number of significant figures in $I, II$ and $III$ is respectively:
$I) 0.0063$
$II) 132.00$
$III) 1004$
The number of significant figures in $I, II$ and $III$ is respectively:
The candela is the luminous intensity,in a given direction,of a source that emits monochromatic radiation of frequency '$A$' $\times 10^{12}$ hertz and that has a radiant intensity in that direction of $\frac{1}{B}$ watt per steradian. '$A$' and '$B$' are respectively
Convert the concentration $0.05 \, M$ into $mol \, cm^{-3}$.
Medium
View SolutionWhat is the $SI$ unit of luminous intensity?
Easy
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