Which of the following ions has 18 electrons | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the number of electrons in the outermost shell,we write the electronic configuration of each ion:$1$. $Cu^{+}$ $(Z=29)$: The configur

Vedclass · Accepted Answer

$Cu^{+}$

Vedclass · Answer

(A) To determine the number of electrons in the outermost shell,we write the electronic configuration of each ion:$1$. $Cu^{+}$ $(Z=29)$: The configuration is $[Ar] 3d^{10}$. The outermost shell is the $3rd$ shell,which contains $18$ electrons ($3s^2 3p^6 3d^{10} = 18$ electrons).$2$. $K^{+}$ $(Z=19)$: The configuration is $[Ne] 3s^2 3p^6$. The outermost shell is the $3rd$ shell,which contains $8$ electrons.$3$. $Cs^{+}$ $(Z=55)$: The configuration is $[Xe] 6s^0$. The outermost shell is the $5th$ shell,which contains $18$ electrons ($5s^2 5p^6 5d^{10} = 18$ electrons).$4$. $Cl^{-}$ $(Z=17)$: The configuration is $[Ne] 3s^2 3p^6$. The outermost shell is the $3rd$ shell,which contains $8$ electrons.Both $Cu^{+}$ and $Cs^{+}$ satisfy the condition of having $18$ electrons in the outermost shell. However,in the context of standard chemistry problems,$Cu^{+}$ is the most common answer for this specific configuration.

Which of the following ions has $18$ electrons in its outermost shell?

Similar Questions

The electronic configuration of an element is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^1$. This represents:

What is the electronic configuration of $Cu^{2+} (Z = 29)$ in its ground state?

Identify the impossible quantum number set for an electron from the following:

The energy is lowest for the orbital :

Which of the following sets of quantum numbers is not allowed?

Vedclass Test Series

Exam Paper Generator

Online Exam Module