If the quantum number values for the valence shell electron of an atom are $n = 4, l = 0, m = 0$,then the atomic number of the element could be .........

The quantum numbers of six electrons are given below. Arrange them in order of increasing energy. If any of these combinations have the same energy,list them:
$(1)$ $n = 4, l = 2, m_l = 2, m_s = -1/2$
$(2)$ $n = 3, l = 2, m_l = 1, m_s = +1/2$
$(3)$ $n = 4, l = 1, m_l = 0, m_s = +1/2$
$(4)$ $n = 3, l = 2, m_l = -2, m_s = -1/2$
$(5)$ $n = 3, l = 1, m_l = -1, m_s = +1/2$
$(6)$ $n = 4, l = 1, m_l = 0, m_s = +1/2$

For principal quantum number $n = 4$,the total number of orbitals having $l = 3$ is:

Explain the energy order of orbitals in multielectron atoms.

When the $3d$ orbital is complete,the next electron will enter the

When the $4d$ orbital is complete,the newly entering electron goes into which orbital?