According to the Aufbau principle,which orbit | vedclass

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(A) According to the Aufbau principle,the order of filling of orbitals is determined by the $(n+l)$ rule. For $5f$ orbital,$n=5$ and $l=3$,so $(n+l) =

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$6d$

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(A) According to the Aufbau principle,the order of filling of orbitals is determined by the $(n+l)$ rule. For $5f$ orbital,$n=5$ and $l=3$,so $(n+l) = 5+3 = 8$. For $6d$ orbital,$n=6$ and $l=2$,so $(n+l) = 6+2 = 8$. Since the $(n+l)$ values are equal,the orbital with the lower $n$ value is filled first. After $5f$ $(n=5, l=3)$ and $6d$ $(n=6, l=2)$,the next orbital in the sequence is $7p$ $(n=7, l=1)$ or $7s$ $(n=7, l=0)$. Following the energy sequence $1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p$,the orbital filled immediately after $5f$ is $6d$.

According to the Aufbau principle,which orbital is filled with electrons immediately after the $5f$ orbital?

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