If you are driving a car of mass 1050 , kg at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Heisenberg's uncertainty principle,$\Delta x \cdot \Delta p \geq \frac{h}{4\pi}$.Since $\Delta p = m \cdot \Delta v$,the equation bec

Vedclass · Accepted Answer

$\geq 2 	imes 10^{-37} \, m$

Vedclass · Answer

(C) According to Heisenberg's uncertainty principle,$\Delta x \cdot \Delta p \geq \frac{h}{4\pi}$.Since $\Delta p = m \cdot \Delta v$,the equation becomes $\Delta x \cdot m \cdot \Delta v \geq \frac{h}{4\pi}$.Given: $m = 1050 \, kg$,$v = 90 \, km/h = 90 	imes \frac{5}{18} = 25 \, m/s$.Uncertainty in velocity $\Delta v = 1 \, \% 	ext{ of } 25 \, m/s = 0.25 \, m/s$.Using $h = 6.626 	imes 10^{-34} \, J \cdot s$:$\Delta x \geq \frac{6.626 	imes 10^{-34}}{4 	imes 3.1416 	imes 1050 	imes 0.25}$.$\Delta x \geq \frac{6.626 	imes 10^{-34}}{3298.68} \approx 2.008 	imes 10^{-37} \, m$.Thus,$\Delta x \geq 2 	imes 10^{-37} \, m$.

If you are driving a car of mass $1050 \, kg$ at a speed of $90 \, km/h$ and the uncertainty in the velocity of the car is $1 \, \%$,what will be the uncertainty in its position?

Similar Questions

What is the uncertainty product $\Delta v \cdot \Delta x$ for a particle of mass $1 \ mg$? What does this imply?

The Bohr model of an atom is contradicted by

If the uncertainty in position and momentum are equal,then the uncertainty in velocity is .......

What is Quantum mechanics?

If uncertainties in the measurement of position and momentum of a microscopic object of mass $m$ are equal,then the uncertainty in the measurement of velocity is given by the expression:

Vedclass Test Series

Exam Paper Generator

Online Exam Module