The wavelength of a particle having an Einste | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The Einstein energy $E$ is given by the formula: $E = \frac{N_A hc}{\lambda}$.
Given: $E = 1.995 	imes 10^{12} \ erg \ mol^{-1} = 1.995 	imes 1

Vedclass · Accepted Answer

$6000$

Vedclass · Answer

(D) The Einstein energy $E$ is given by the formula: $E = \frac{N_A hc}{\lambda}$.
Given: $E = 1.995 	imes 10^{12} \ erg \ mol^{-1} = 1.995 	imes 10^5 \ J \ mol^{-1}$ (since $1 \ J = 10^7 \ erg$).
Using $N_A = 6.022 	imes 10^{23} \ mol^{-1}$,$h = 6.626 	imes 10^{-34} \ J \ s$,and $c = 3 	imes 10^8 \ m \ s^{-1}$:
$\lambda = \frac{N_A hc}{E} = \frac{6.022 	imes 10^{23} 	imes 6.626 	imes 10^{-34} 	imes 3 	imes 10^8}{1.995 	imes 10^5}$.
$\lambda \approx \frac{1.197 	imes 10^{-1}}{1.995 	imes 10^5} \approx 6 	imes 10^{-7} \ m$.
Converting to $\mathring{A}: 6 	imes 10^{-7} \ m = 6000 \ \mathring{A}$.

The wavelength of a particle having an Einstein energy of $1.995 \times 10^{12} \ erg \ mol^{-1} \ photon^{-1}$ is .......... $\mathring{A}$.

Similar Questions

For a hydrogen atom with $n = 1$,the radius of the Bohr orbit is approximately $0.530 \, \mathring{A}$. What will be the radius for the first excited state $(n = 2)$ in $\mathring{A}$?

Bohr's radius can have

If the radius of the second Bohr orbit of the $He^{+}$ ion is $105.8 \, pm$, what is the radius of the third Bohr orbit of the $Li^{2+}$ ion?

Describe the hydrogen spectrum.

Based on equation $E = -2.178 \times 10^{-18} \ J \ \frac{Z^2}{n^2}$,certain conclusions are written. Which of them is not correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module