$0.1 \ mol$ of $N_2O_{4(g)}$ was sealed in a tube under $1 \ atm$ pressure at $25\,^oC$. Calculate the number of moles of $NO_{2(g)}$ present,if the equilibrium $N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}$ $(K_p = 0.14)$ is reached.

For the following gaseous reaction $H_2(g) + I_2(g) \rightleftharpoons 2HI(g)$,the equilibrium constant relationship is:

$A$ mixture of $1 \ mol$ of $H_2O$ and $1 \ mol$ of $CO$ is taken in a $10 \ L$ container and heated to $725 \ K$. At equilibrium,$40\%$ of water reacts with carbon monoxide according to the equation:
$CO_{(g)} + H_2O_{(g)} \rightleftharpoons CO_{2(g)} + H_{2(g)}$
The equilibrium constant $K_C \times 10^2$ for the reaction is $.......$ (Nearest integer).

The plot of $log_{10} K$ vs $\frac{1}{T}$ gives a straight line. The intercept and slope respectively are (where $K$ is equilibrium constant).

$A$ schematic plot of $\ln K_{eq}$ versus inverse of temperature $(1/T)$ for a reaction is shown below. The reaction must be

Equilibrium constant for the reaction $H_2O_{(g)} + CO_{(g)} \rightleftharpoons H_{2(g)} + CO_{2(g)}$ is $81$. If the velocity constant of the forward reaction is $162 \ L \ mol^{-1} \ s^{-1}$,what is the velocity constant (in $L \ mol^{-1} \ s^{-1}$) for the backward reaction?