The mass to charge ratio (m/e) of a cation is | vedclass

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(C) The mass to charge ratio is given as $\frac{m}{e} = 1.5 	imes 10^{-8} \ kg/C$. Assuming the ion has a unit positive charge,$e = 1.602 	imes 10^{

Vedclass · Accepted Answer

$2.4 	imes 10^{-24} \ g$

Vedclass · Answer

(C) The mass to charge ratio is given as $\frac{m}{e} = 1.5 	imes 10^{-8} \ kg/C$. Assuming the ion has a unit positive charge,$e = 1.602 	imes 10^{-19} \ C$. Therefore,the mass $m = (1.5 	imes 10^{-8} \ kg/C) 	imes (1.602 	imes 10^{-19} \ C) \approx 2.403 	imes 10^{-27} \ kg$. Converting to grams: $m = 2.403 	imes 10^{-27} \ kg 	imes 10^3 \ g/kg = 2.403 	imes 10^{-24} \ g$.

The mass to charge ratio $(m/e)$ of a cation is $1.5 \times 10^{-8} \ kg/C$. What is the mass of the ion?

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