The Kelvin temperature of an ideal gas is pro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to the kinetic molecular theory of gases,the average kinetic energy $(KE_{avg})$ of an ideal gas is given by the formula: $KE_{avg} = \f

Vedclass · Accepted Answer

The average kinetic energy of the molecules

Vedclass · Answer

(B) According to the kinetic molecular theory of gases,the average kinetic energy $(KE_{avg})$ of an ideal gas is given by the formula: $KE_{avg} = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ is the temperature in Kelvin. This equation shows that the average kinetic energy of the gas molecules is directly proportional to the absolute temperature $(T)$ of the gas.

The Kelvin temperature of an ideal gas is proportional to:

Similar Questions

What is an elastic molecular collision?

$0.5 \text{ mole}$ of each of $H_{2}$,$SO_{2}$,and $CH_{4}$ are kept in a container. $A$ hole was made in the container. After $3 \text{ h}$,the order of partial pressures in the container will be

Which of the following relations is correct for an ideal gas?

The postulates of the kinetic molecular theory are related to what?

Assuming ideal behaviour,the ratio of kinetic energies of $3 \ g$ of $H_2$ and $4 \ g$ of $O_2$ at any temperature is

Vedclass Test Series

Exam Paper Generator

Online Exam Module