The root mean square speed of O_2 at STP is . | vedclass

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(A) The formula for root mean square speed $(u_{rms})$ is given by $u_{rms} = \sqrt{\frac{3RT}{M}}$.At $STP$,$T = 273.15 \ K$ and $R = 8.314 \ J \cdot

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$4.61 	imes 10^4$

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(A) The formula for root mean square speed $(u_{rms})$ is given by $u_{rms} = \sqrt{\frac{3RT}{M}}$.At $STP$,$T = 273.15 \ K$ and $R = 8.314 \ J \cdot K^{-1} \cdot mol^{-1}$.The molar mass of $O_2$ $(M)$ is $32 \ g/mol = 32 	imes 10^{-3} \ kg/mol$.Substituting the values: $u_{rms} = \sqrt{\frac{3 	imes 8.314 	imes 273.15}{32 	imes 10^{-3}}} \approx \sqrt{\frac{6813.5}{0.032}} \approx \sqrt{212922} \approx 461.4 \ m/s$.To convert $m/s$ to $cm/s$,multiply by $100$: $461.4 	imes 100 = 46140 \ cm/s = 4.614 	imes 10^4 \ cm/s$.

The root mean square speed of $O_2$ at $STP$ is ........ $cm/s$.

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