Pb + text{Dil. } HNO_3 xrightarrow{text{Warm} | vedclass

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Question

(C) The reaction of lead $(Pb)$ with dilute nitric acid $(HNO_3)$ is given by:$3Pb + 8HNO_3 (	ext{dil.}) \xrightarrow{\Delta} 3Pb(NO_3)_2 + 2NO\uparr

Vedclass · Accepted Answer

It combines with $Fe_2(SO_4)_3$

Vedclass · Answer

(C) The reaction of lead $(Pb)$ with dilute nitric acid $(HNO_3)$ is given by:$3Pb + 8HNO_3 (	ext{dil.}) \xrightarrow{\Delta} 3Pb(NO_3)_2 + 2NO\uparrow + 4H_2O$Here,$Q$ is $NO$ (Nitric oxide).$NO$ is a paramagnetic colourless gas. (Statement $A$ is correct).$NO$ reacts with $O_2$ in the air to form $NO_2$,which is a paramagnetic brown coloured gas. (Statement $B$ is correct).$NO$ reacts with $FeSO_4$ to form a brown ring complex $[Fe(H_2O)_5(NO)]SO_4$,but it does not combine with $Fe_2(SO_4)_3$. (Statement $C$ is incorrect).$HNO_2$ undergoes disproportionation to form $HNO_3$ and $NO$. (Statement $D$ is correct).Therefore,the incorrect statement is $C$.

$Pb + \text{Dil. } HNO_3 \xrightarrow{\text{Warm}} P + Q\uparrow + H_2O$
Incorrect statement for $Q$ is

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$Pb + \text{Dil. } HNO_3 \xrightarrow{\text{Warm}} P + Q\uparrow + H_2O$Incorrect statement for $Q$ is