CHO-(CHOH)_4-CH_2OH xrightarrow{HIO_4} text{P | vedclass

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Question

(B) Periodic acid $(HIO_4)$ cleaves the $C-C$ bonds of vicinal diols and $\alpha$-hydroxy carbonyl compounds.In glucose $(CHO-(CHOH)_4-CH_2OH)$,there

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$5HCOOH + HCHO$

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(B) Periodic acid $(HIO_4)$ cleaves the $C-C$ bonds of vicinal diols and $\alpha$-hydroxy carbonyl compounds.In glucose $(CHO-(CHOH)_4-CH_2OH)$,there are $5$ such bonds that are cleaved.The aldehyde group $(-CHO)$ and the four secondary alcohol groups $(-CHOH-)$ are oxidized to formic acid $(HCOOH)$,while the terminal primary alcohol group $(-CH_2OH)$ is oxidized to formaldehyde $(HCHO)$.The reaction is:$CHO-(CHOH)_4-CH_2OH + 5HIO_4 \rightarrow 5HCOOH + HCHO + 5HIO_3 + H_2O$

$CHO-(CHOH)_4-CH_2OH \xrightarrow{HIO_4} \text{Product}$. Identify the product.

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