CH_3-CO-CH_2-COOCH_3 xrightarrow[H_2O]{H^{+}} | vedclass

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(C) Step $1$: Acidic hydrolysis of the ester group in methyl acetoacetate gives acetoacetic acid $(A)$.
$CH_3-CO-CH_2-COOCH_3 + H_2O \xrightarrow{H^{

Vedclass · Accepted Answer

$CH_3-CO-CH_3$,$CH_3-C(OH)(CN)-CH_3$

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(C) Step $1$: Acidic hydrolysis of the ester group in methyl acetoacetate gives acetoacetic acid $(A)$.
$CH_3-CO-CH_2-COOCH_3 + H_2O \xrightarrow{H^{+}} CH_3-CO-CH_2-COOH (A) + CH_3OH$
Step $2$: Heating acetoacetic acid (a $\beta$-keto acid) causes decarboxylation to form acetone $(B)$.
$CH_3-CO-CH_2-COOH \xrightarrow{\Delta} CH_3-CO-CH_3 (B) + CO_2$
Step $3$: Nucleophilic addition of $HCN$ to acetone forms acetone cyanohydrin $(C)$.
$CH_3-CO-CH_3 + HCN \rightarrow CH_3-C(OH)(CN)-CH_3 (C)$

$CH_3-CO-CH_2-COOCH_3$ $\xrightarrow[H_2O]{H^{+}} A$ $\xrightarrow{\Delta} B$ $\xrightarrow{HCN} C$. What are $B$ and $C$?

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