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(C) The reaction involves the acid-catalyzed dehydration of a secondary alcohol $(1-cyclohexylethanol)$.$1$. Protonation of the hydroxyl group: The $-

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$1-Ethylcyclohex-1-ene$

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(C) The reaction involves the acid-catalyzed dehydration of a secondary alcohol $(1-cyclohexylethanol)$.$1$. Protonation of the hydroxyl group: The $-OH$ group is protonated by $H^+$ from $Conc. H_2SO_4$ to form a good leaving group $(-OH_2^+)$.$2$. Formation of carbocation: Loss of water molecule generates a secondary carbocation at the carbon atom attached to the cyclohexane ring.$3$. Rearrangement: The secondary carbocation undergoes a $1,2-hydride$ shift to form a more stable tertiary carbocation (the positive charge moves to the carbon on the ring).$4$. Elimination: Loss of a proton from the adjacent carbon leads to the formation of the most stable alkene,which is the $Saytzeff$ product,$1-ethylcyclohex-1-ene$.

Predict the major product for the following reaction:
$Cyclohexyl-CH(OH)-CH_3 \xrightarrow[\Delta]{Conc. H_2SO_4} \text{Major Product}$

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Predict the major product for the following reaction:$Cyclohexyl-CH(OH)-CH_3 \xrightarrow[\Delta]{Conc. H_2SO_4} \text{Major Product}$