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(A) The given reaction is Hydroboration-Oxidation of an alkene.$1$. The reagent $(i) B_2H_6(THF)$ followed by $(ii) H_2O_2, NaOH$ performs anti-Markov

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$2-Cyclopentylethanol$

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(A) The given reaction is Hydroboration-Oxidation of an alkene.$1$. The reagent $(i) B_2H_6(THF)$ followed by $(ii) H_2O_2, NaOH$ performs anti-Markovnikov addition of water across the double bond.$2$. The hydroxyl group $(-OH)$ attaches to the less substituted carbon atom of the double bond.$3$. In the reactant,vinylcyclopentane,the terminal carbon of the vinyl group is less substituted than the carbon attached to the cyclopentyl ring.$4$. Therefore,the $-OH$ group adds to the terminal carbon,resulting in the formation of $2-cyclopentylethanol$.

Predict the major product for the following reaction:
$Cyclopentyl-ethene \xrightarrow[(ii) H_2O_2, NaOH]{(i) B_2H_6(THF)} ?$

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Predict the major product for the following reaction:$Cyclopentyl-ethene \xrightarrow[(ii) H_2O_2, NaOH]{(i) B_2H_6(THF)} ?$