$Xe + F_2 \xrightarrow[673 \ K]{Ni}$
Which compound is formed by the above reaction?
Which compound is formed by the above reaction?
- A$XeF_4$
- B$XeF_2$
- C$XeF_6$
- DNone of these
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Similar Questions
Which of the following is not true about helium?
Identify all the products formed when $XeF_4$ is completely hydrolysed.
Select the correct matching.
List-$I$ List-$II$ $A$. $XeF_4$ $1$. Pyramidal $B$. $XeF_6$ $2$. $T$-shape $C$. $XeO_3$ $3$. Distorted octahedral $D$. $XeOF_2$ $4$. Square planar
| List-$I$ | List-$II$ |
|---|---|
| $A$. $XeF_4$ | $1$. Pyramidal |
| $B$. $XeF_6$ | $2$. $T$-shape |
| $C$. $XeO_3$ | $3$. Distorted octahedral |
| $D$. $XeOF_2$ | $4$. Square planar |
Easy
View SolutionThe shape of $XeOF_4$ molecule is
Medium
View SolutionObserve the following reaction: $XeF_4 + SbF_5 \rightarrow [XeF_3]^+ [SbF_6]^-$. The correct statement$(s)$ regarding the product is/are:
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