(C) Let the oxidation state of $Xe$ be $x$. In $XeOF_2$,the oxidation state of $O$ is $-2$ and $F$ is $-1$. The sum of oxidation states in a neutral m

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(C) Let the oxidation state of $Xe$ be $x$. In $XeOF_2$,the oxidation state of $O$ is $-2$ and $F$ is $-1$. The sum of oxidation states in a neutral molecule is $0$. $x + (-2) + 2(-1) = 0$ $x - 2 - 2 = 0$ $x - 4 = 0$ $x = +4$. Therefore,the oxidation state of $Xe$ is $+4$.