(A) When $H_2S$ is burned in a limited supply of oxygen,it forms water and sulfur: $2H_2S + O_2 \to 2H_2O + 2S$ When burned in excess oxygen,it forms

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(A) When $H_2S$ is burned in a limited supply of oxygen,it forms water and sulfur: $2H_2S + O_2 \to 2H_2O + 2S$ When burned in excess oxygen,it forms sulfur dioxide: $2H_2S + 3O_2 \to 2H_2O + 2SO_2$ Given the options,the reaction producing water and sulfur is the standard representation for the combustion of $H_2S$ in limited oxygen.