MF + XeF_4 to 'A' (M^{+} = Alkali metal catio | vedclass

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Question

(C) The reaction between an alkali metal fluoride $(MF)$ and xenon tetrafluoride $(XeF_4)$ results in the formation of the complex salt $M[XeF_5]$.$MF

Vedclass · Accepted Answer

$sp^3d^3$,pentagonal planar

Vedclass · Answer

(C) The reaction between an alkali metal fluoride $(MF)$ and xenon tetrafluoride $(XeF_4)$ results in the formation of the complex salt $M[XeF_5]$.$MF + XeF_4 	o M^{+}[XeF_5]^{-}$.In the $[XeF_5]^{-}$ anion,the central xenon atom has $5$ bond pairs and $2$ lone pairs of electrons,resulting in a total of $7$ electron pairs.This corresponds to $sp^3d^3$ hybridisation.The shape of the $[XeF_5]^{-}$ ion is pentagonal planar.

$MF + XeF_4 \to$ '$A$' ($M^{+} =$ Alkali metal cation). The state of hybridisation of the central atom in '$A$' and shape of the species are:

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