B(OH)_3 + NaOH to NaBO_2 + Na[B(OH)_4] + H_2O | vedclass

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(A) $H_3BO_3$ acts as a weak monobasic Lewis acid.$(i)$ The reaction $B(OH)_3 + NaOH \rightleftharpoons Na[B(OH)_4]$ is an equilibrium process.$(ii)$

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addition of cis-$1, 2-$diol

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(A) $H_3BO_3$ acts as a weak monobasic Lewis acid.$(i)$ The reaction $B(OH)_3 + NaOH \rightleftharpoons Na[B(OH)_4]$ is an equilibrium process.$(ii)$ Upon the addition of cis-$1, 2-$diol (such as glycerol or mannitol) to the $H_3BO_3$ solution,a stable chelate complex is formed.$(iii)$ This chelation removes the $[B(OH)_4]^-$ ions from the solution,shifting the equilibrium to the right according to Le Chatelier's principle,thereby increasing the acidic strength of $H_3BO_3$.

$B(OH)_3 + NaOH \to NaBO_2 + Na[B(OH)_4] + H_2O$
How can this reaction be made to proceed in the forward direction?

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$B(OH)_3 + NaOH \to NaBO_2 + Na[B(OH)_4] + H_2O$How can this reaction be made to proceed in the forward direction?