[Co(NH_3)_6]^{+2} is paramagnetic in nature d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The atomic number of $Co$ is $27$. The electronic configuration of $Co$ is $[Ar] 3d^7 4s^2$.In $[Co(NH_3)_6]^{+2}$,the oxidation state of $Co$ is

Vedclass · Accepted Answer

$3d$

Vedclass · Answer

(A) The atomic number of $Co$ is $27$. The electronic configuration of $Co$ is $[Ar] 3d^7 4s^2$.In $[Co(NH_3)_6]^{+2}$,the oxidation state of $Co$ is $+2$. Thus,the configuration of $Co^{+2}$ is $[Ar] 3d^7$.In the presence of $NH_3$ (a strong field ligand),the electrons in the $3d$ orbitals rearrange.For $Co^{+2}$ $(3d^7)$,the distribution is $t_{2g}^5 e_g^2$.This results in $3$ unpaired electrons in the $3d$ orbitals,making the complex paramagnetic.

$[Co(NH_3)_6]^{+2}$ is paramagnetic in nature due to the presence of unpaired $e^-$ in

Similar Questions

The hexafluoroferrate$(III)$ ion is an outer orbital complex. The number of unpaired electrons in it is.....

The complex ion $[Fe(CN)_6]^{4-}$ contains

Explain why $[Co(NH_{3})_{6}]^{3+}$ is an inner orbital complex whereas $[Ni(NH_{3})_{6}]^{2+}$ is an outer orbital complex.

$Mn^{2+}$ forms a complex with $Br^{-}$ ion. The magnetic moment of the complex is $5.92 \ B.M.$ What could not be the probable formula and geometry of the complex?

The hybridization states of the central atom in the complexes $[Fe(CN)_6]^{3-}$,$[Fe(CN)_6]^{4-}$ and $[Co(NO_2)_6]^{3-}$ are

Vedclass Test Series

Exam Paper Generator

Online Exam Module