CH_3-C(CH_3)=CH_2 xrightarrow[R_2O_2]{HBr} X | vedclass

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(A) The addition of $HBr$ to isobutylene $(2-	ext{methylpropene})$ in the presence of peroxide $(R_2O_2)$ follows the Anti-Markovnikov rule,resulting

Vedclass · Accepted Answer

$X = CH_3-CH(CH_3)-CH_2-Br$,$Y = CH_3-CH(CH_3)-CH_2-OCH_3$

Vedclass · Answer

(A) The addition of $HBr$ to isobutylene $(2-	ext{methylpropene})$ in the presence of peroxide $(R_2O_2)$ follows the Anti-Markovnikov rule,resulting in the formation of isobutyl bromide $(X = CH_3-CH(CH_3)-CH_2-Br)$.Subsequent reaction of $X$ with sodium methoxide $(CH_3ONa)$,which is a strong nucleophile,leads to an $S_N2$ reaction to form isobutyl methyl ether $(Y = CH_3-CH(CH_3)-CH_2-OCH_3)$.

$CH_3-C(CH_3)=CH_2$ $\xrightarrow[R_2O_2]{HBr} X$ $\xrightarrow{CH_3ONa} Y$; $X$ and $Y$ are:

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