C_6H_5NH_2 xrightarrow[0-5,^{circ}C]{HCl + Na | vedclass

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(A) $1$. $C_6H_5NH_2$ (Aniline) reacts with $HCl + NaNO_2$ at $0-5\,^{\circ}C$ to form $C_6H_5N_2^+Cl^-$ (Benzenediazonium chloride),which is $A$.$2$.

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$C_6H_5CH_2OH$

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(A) $1$. $C_6H_5NH_2$ (Aniline) reacts with $HCl + NaNO_2$ at $0-5\,^{\circ}C$ to form $C_6H_5N_2^+Cl^-$ (Benzenediazonium chloride),which is $A$.$2$. $A$ reacts with $CuCN$ (Sandmeyer reaction) to form $C_6H_5CN$ (Benzonitrile),which is $B$.$3$. $B$ undergoes catalytic hydrogenation with $H_2/Ni$ to form $C_6H_5CH_2NH_2$ (Benzylamine),which is $C$.$4$. $C$ reacts with $HNO_2$ (Nitrous acid) to form $C_6H_5CH_2OH$ (Benzyl alcohol),which is $D$.

$C_6H_5NH_2$ $\xrightarrow[0-5\,^{\circ}C]{HCl + NaNO_2} A$ $\xrightarrow{CuCN} B$ $\xrightarrow{H_2/Ni} C$ $\xrightarrow{HNO_2} D$
The structure of $D$ is

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$C_6H_5NH_2$ $\xrightarrow[0-5\,^{\circ}C]{HCl + NaNO_2} A$ $\xrightarrow{CuCN} B$ $\xrightarrow{H_2/Ni} C$ $\xrightarrow{HNO_2} D$The structure of $D$ is