Ph-O-CH_2-Ph xrightarrow{HI} A + B will be | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the reaction of benzyl phenyl ether $(Ph-O-CH_2-Ph)$ with $HI$,the cleavage occurs at the $O-CH_2$ bond rather than the $O-Ph$ bond.This is bec

Vedclass · Accepted Answer

$Ph-OH + Ph-CH_2-I$

Vedclass · Answer

(A) In the reaction of benzyl phenyl ether $(Ph-O-CH_2-Ph)$ with $HI$,the cleavage occurs at the $O-CH_2$ bond rather than the $O-Ph$ bond.This is because the $C-O$ bond in $Ph-O$ has partial double bond character due to resonance with the benzene ring,making it stronger.The $I^-$ nucleophile attacks the benzyl carbon to form benzyl iodide $(Ph-CH_2-I)$,and the oxygen remains with the phenyl ring to form phenol $(Ph-OH)$.

$Ph-O-CH_2-Ph \xrightarrow{HI} A + B$ will be

Similar Questions

The reaction of chloroethane with $Y$ gives $NaCl$ and $Z$. The reaction of one mole of $Z$ with two moles of $HI$ gives water and iodoethane. What is $Y$?

Product $(B)$ is

The main product of the following reaction will be:

Which of the following aromatic ethers does not undergo cleavage by $HI$ at $525 \ K$?

Which of the following compounds will not give benzoic acid upon boiling with alkaline $KMnO_4$ followed by acidification?

Vedclass Test Series

Exam Paper Generator

Online Exam Module