$CH_3-C \equiv C-CH_3$ $\xrightarrow{H^{+}/KMnO_4, \Delta} A$ $\xrightarrow{(1) LiAlH_4, (2) H^{+}} B$
$B$ will be

  • A
    $CH_3-COOH$
  • B
    $CH_3-CH_2-OH$
  • C
    $CH_3-CHO$
  • D
    $CH_3-CO-CO-CH_3$

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