0.27 g of a long chain fatty acid was dissol | vedclass

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Question

(D) Total mass of fatty acid $= 0.27 \ g$ in $100 \ mL$ of solution.Mass of fatty acid in $10 \ mL$ of solution $= 0.27 	imes \frac{10}{100} = 0.027

Vedclass · Accepted Answer

$10^{-6} \ m$

Vedclass · Answer

(D) Total mass of fatty acid $= 0.27 \ g$ in $100 \ mL$ of solution.Mass of fatty acid in $10 \ mL$ of solution $= 0.27 	imes \frac{10}{100} = 0.027 \ g$.Volume of fatty acid $= \frac{	ext{Mass}}{	ext{Density}} = \frac{0.027 \ g}{0.9 \ g \ cm^{-3}} = 0.03 \ cm^3$.Area of the monolayer on the watch glass $= \pi r^2 = 3 	imes (10 \ cm)^2 = 300 \ cm^2$.Height of the monolayer $= \frac{	ext{Volume}}{	ext{Area}} = \frac{0.03 \ cm^3}{300 \ cm^2} = 10^{-4} \ cm$.Converting to meters: $10^{-4} \ cm = 10^{-4} 	imes 10^{-2} \ m = 10^{-6} \ m$.

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