The reaction R-C(=O)-R + HCN xrightarrow{text | vedclass

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(C) The reaction involves the nucleophilic attack of the cyanide ion $(CN^{-})$ on the carbonyl carbon. To generate $CN^{-}$ from $HCN$,a base is requ

Vedclass · Accepted Answer

$EtO^{-}$

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(C) The reaction involves the nucleophilic attack of the cyanide ion $(CN^{-})$ on the carbonyl carbon. To generate $CN^{-}$ from $HCN$,a base is required to abstract the proton from $HCN$. The base used must be stronger than the cyanide ion $(CN^{-})$ to effectively shift the equilibrium towards the formation of $CN^{-}$. Among the given options,the ethoxide ion $(EtO^{-})$ is a stronger base than the cyanide ion $(CN^{-})$,making it an effective catalyst for this reaction.

Column-$I$ (Compound)	Column-$II$ (Attraction Forces)
$A$. Aldehyde	$i$. Intermolecular hydrogen bond formed in $ROH$ between $O^{\delta -}$ of one molecule and $H^{\delta +}$ of another molecule.
$B$. Ketone	$ii$. Dipole-dipole forces between $C^{\delta +}$ of one molecule and $O^{\delta -}$ of another molecule.
$C$. Alcohol	$iii$. van der Waals forces
$D$. Alkane	$iv$. Ionic forces

The reaction $R-C(=O)-R + HCN \xrightarrow{\text{catalyst}} R-C(OH)(CN)-R$ is a nucleophilic addition reaction. Which of the following can be used as a catalyst in the above reaction?

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