The reaction sequence is as follows:HOOC-CH_2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. The starting material is adipic acid $(HOOC-(CH_2)_4-COOH)$. Heating a dicarboxylic acid with $BaCO_3$ leads to the formation of a cyclic ket

Vedclass · Accepted Answer

Cyclopentane

Vedclass · Answer

(C) $1$. The starting material is adipic acid $(HOOC-(CH_2)_4-COOH)$. Heating a dicarboxylic acid with $BaCO_3$ leads to the formation of a cyclic ketone via decarboxylation and cyclization. Thus,$A$ is cyclopentanone.$2$. The reaction of cyclopentanone $(A)$ with hydrazine $(NH_2-NH_2)$ forms the corresponding hydrazone,which is $B$ (cyclopentanone hydrazone).$3$. The reaction of the hydrazone $(B)$ with $KOH$ and heat is the Wolff-Kishner reduction,which reduces the carbonyl group to a methylene group $(-CH_2-)$. Thus,$C$ is cyclopentane.

The reaction sequence is as follows:
$HOOC-CH_2-CH_2-CH_2-CH_2-COOH$ $\xrightarrow[BaCO_3]{\Delta} A$ $\xrightarrow{NH_2-NH_2} B$ $\xrightarrow[KOH]{\text{heat}} C$
The final product $(C)$ obtained is:

Similar Questions

The product obtained in this reaction is:

Which of the following undergoes haloform reaction?
$ (i) \ CH_3CH_2COCH_2Cl $
$ (ii) \ C_6H_5COCH_3 $
$ (iii) \ C_6H_5COCHCl_2 $
$ (iv) \ CH_3CH_2COCCl_3 $

Comment on the stereochemistry of the products for the following reaction:
$3$-methylpentan-$2$-one + $CH_3MgBr$ followed by $NH_4Cl$ workup.

Total number of nucleophiles from the following is $:-$ $NH_3, PhSH, (H_3C)_2S, H_2C=CH_2, \stackrel{\ominus}{O}H, H_3O^{\oplus}, (CH_3)_2CO, CH_3CH=NCH_3$

Which does not react with Fehling solution?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The reaction sequence is as follows:$HOOC-CH_2-CH_2-CH_2-CH_2-COOH$ $\xrightarrow[BaCO_3]{\Delta} A$ $\xrightarrow{NH_2-NH_2} B$ $\xrightarrow[KOH]{\text{heat}} C$The final product $(C)$ obtained is: