$Ph-C(=O)-CH_3$ $\xrightarrow[HCl]{NaNO_2} (A)$ $\xrightarrow[heat]{Ac_2O} (B)$ $\xrightarrow{H_3O^{+}} (C)$
Product $(C)$ of the above reaction is

  • A
    $Ph-CO_2H$
  • B
    $Ph-C(=O)-CO_2H$
  • C
    $Ph-C(=O)-CHO$
  • D
    $Ph-C(=O)-CH_2OH$

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