CH_3-CH(OH)-CH_2-CH_2-CO-CH_3 rightarrow CH_3 | vedclass

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Question

(A) The conversion involves the reduction of a ketone group $(-CO-)$ to a methylene group $(-CH_2-)$ in the presence of an alcohol group $(-OH)$.$1$.

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Wolff-Kishner reduction

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(A) The conversion involves the reduction of a ketone group $(-CO-)$ to a methylene group $(-CH_2-)$ in the presence of an alcohol group $(-OH)$.$1$. $LiAlH_4$ and $NaBH_4$ are reducing agents that reduce ketones to alcohols,not to alkanes.$2$. Clemmensen reduction uses $Zn(Hg)/HCl$ (acidic medium). In acidic conditions,the alcohol group can undergo dehydration or other side reactions.$3$. Wolff-Kishner reduction uses $NH_2NH_2/KOH$ (basic medium). The alcohol group is stable in basic conditions,making this the preferred method for this specific transformation.Therefore,the correct option is $A$.

Column-$I$ (Compound)	Column-$II$ (Attraction Forces)
$A$. Aldehyde	$i$. Intermolecular hydrogen bond formed in $ROH$ between $O^{\delta -}$ of one molecule and $H^{\delta +}$ of another molecule.
$B$. Ketone	$ii$. Dipole-dipole forces between $C^{\delta +}$ of one molecule and $O^{\delta -}$ of another molecule.
$C$. Alcohol	$iii$. van der Waals forces
$D$. Alkane	$iv$. Ionic forces

$CH_3-CH(OH)-CH_2-CH_2-CO-CH_3 \rightarrow CH_3-CH(OH)-(CH_2)_3-CH_3$
The above conversion can be achieved by:

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$CH_3-CH(OH)-CH_2-CH_2-CO-CH_3 \rightarrow CH_3-CH(OH)-(CH_2)_3-CH_3$The above conversion can be achieved by: