CHO-CH(OH)-CH_2OH xrightarrow{2HIO_4} Product | vedclass

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(B) Periodic acid $(HIO_4)$ cleaves vicinal diols and polyols. The reaction is: $CHO-CH(OH)-CH_2OH + 2HIO_4 \rightarrow HCHO + 2HCO_2H + 2HIO_3$. The

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$HCHO, 2HCO_2H$

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(B) Periodic acid $(HIO_4)$ cleaves vicinal diols and polyols. The reaction is: $CHO-CH(OH)-CH_2OH + 2HIO_4 \rightarrow HCHO + 2HCO_2H + 2HIO_3$. The terminal $CH_2OH$ group is oxidized to $HCHO$ (formaldehyde),and the internal $CH(OH)$ group is oxidized to $HCO_2H$ (formic acid). The $CHO$ group is also oxidized to $HCO_2H$. Thus,the products are $HCHO$ and $2HCO_2H$.

$CHO-CH(OH)-CH_2OH \xrightarrow{2HIO_4}$ Products obtained in the above reaction are

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