1, 2, 3-butanetriol undergoes oxidative cleav | vedclass

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(B) $1, 2, 3$-butanetriol has the structure $CH_2(OH)-CH(OH)-CH(OH)-CH_3$. Periodic acid $(HIO_4)$ cleaves the $C-C$ bonds between adjacent carbons th

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$2$ equivalents of $HIO_4$ are consumed and $HCO_2H, HCH=O$ and $CH_3-CH=O$ are formed.

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(B) $1, 2, 3$-butanetriol has the structure $CH_2(OH)-CH(OH)-CH(OH)-CH_3$. Periodic acid $(HIO_4)$ cleaves the $C-C$ bonds between adjacent carbons that both carry hydroxyl groups. $1.$ The bond between $C1$ and $C2$ is cleaved,and the bond between $C2$ and $C3$ is cleaved. $2.$ This requires $2$ equivalents of $HIO_4$. $3.$ The terminal primary alcohol group $(C1)$ is oxidized to formaldehyde $(HCH=O)$. $4.$ The internal secondary alcohol group $(C2)$,which is between two cleavage sites,is oxidized to formic acid $(HCO_2H)$. $5.$ The secondary alcohol group $(C3)$ is oxidized to acetaldehyde $(CH_3CH=O)$. Therefore,$2$ equivalents of $HIO_4$ are consumed to form $HCO_2H, HCHO,$ and $CH_3CHO$.

$1, 2, 3$-butanetriol undergoes oxidative cleavage with $HIO_4$. During this process:

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