The reaction sequence is: $Br-(CH_2)_{12}-C\equiv CH$ $\xrightarrow{NaNH_2} (A)$ $\xrightarrow[Catalyst]{Lindlar} (B)$. The product $(B)$ is:

  • A
    $A$ cyclic alkene with a trans-double bond.
  • B
    $A$ cyclic alkene with a cis-double bond.
  • C
    $A$ cyclic alkane.
  • D
    $A$ linear alkyne.

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