CH_2 = CH - CH = CH - CH = CH_2How many geome | vedclass

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(A) The compound is $1,3,5$-hexatriene. It has three double bonds. The double bonds at positions $1$ and $5$ are terminal $(CH_2=CH-)$,so they cannot

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$2$

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(A) The compound is $1,3,5$-hexatriene. It has three double bonds. The double bonds at positions $1$ and $5$ are terminal $(CH_2=CH-)$,so they cannot exhibit geometrical isomerism. Only the middle double bond at position $3$ can exhibit geometrical isomerism. Therefore,there are $2$ possible geometrical isomers: $cis$ and $trans$ across the middle $\pi$-bond. Thus,the correct option is $A$.

$CH_2 = CH - CH = CH - CH = CH_2$
How many geometrical isomers are possible for this compound?

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$CH_2 = CH - CH = CH - CH = CH_2$How many geometrical isomers are possible for this compound?