p- orbitals of an atom in the presence of a m | vedclass

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(B) In the absence of a magnetic field,the three $p-$orbitals $(p_x, p_y, p_z)$ are degenerate,meaning they have the same energy.In the presence of an

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Three fold degenerate

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(B) In the absence of a magnetic field,the three $p-$orbitals $(p_x, p_y, p_z)$ are degenerate,meaning they have the same energy.In the presence of an external magnetic field,the degeneracy is lifted only if the orbitals have different energies due to their orientation relative to the field (Zeeman effect).However,in the absence of an external field or when considering the intrinsic nature of the orbitals in a free atom,they are considered $3-$fold degenerate.If the question implies the state in a magnetic field where the energy levels split,they become non-degenerate; however,in standard chemistry contexts regarding the set of $p-$orbitals,they are described as $3-$fold degenerate.

List-$I$ (Quantum number)	List-$II$ (Orbital)
$a. n=2, \ell=1$	$i. 2s$
$b. n=3, \ell=2$	$ii. 3s$
$c. n=3, \ell=0$	$iii. 2p$
$d. n=2, \ell=0$	$iv. 3d$

$p-$ orbitals of an atom in the presence of a magnetic field are

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An ion with a charge of $-2$ has the electronic configuration $1s^2, 2s^2, 2p^6$. Identify the ion.

Match List-$I$ with List-$II$ :
List-$I$ (Quantum number) List-$II$ (Orbital)
$a. n=2, \ell=1$ $i. 2s$
$b. n=3, \ell=2$ $ii. 3s$
$c. n=3, \ell=0$ $iii. 2p$
$d. n=2, \ell=0$ $iv. 3d$

Choose the correct answer from the options given below :

On the basis of which rules does the arrangement of electrons take place in atoms?

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