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(B) Step $1$: Dehydrohalogenation of $2$-chloro-$3$-methylbutane with $C_2H_5ONa / C_2H_5OH$ follows the $E2$ mechanism. According to Saytzeff's rule,

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Acetone $+$ Ethanoic acid

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(B) Step $1$: Dehydrohalogenation of $2$-chloro-$3$-methylbutane with $C_2H_5ONa / C_2H_5OH$ follows the $E2$ mechanism. According to Saytzeff's rule,the more substituted alkene is the major product $(B)$.$(CH_3)_2CH-CHCl-CH_3 \xrightarrow{C_2H_5ONa} (CH_3)_2C=CH-CH_3$ ($2$-methylbut-$2$-ene).Step $2$: Ozonolysis of $2$-methylbut-$2$-ene with oxidative workup $(O_3 / H_2O_2)$ cleaves the double bond to form a ketone and a carboxylic acid.$(CH_3)_2C=CH-CH_3 \xrightarrow{O_3 / H_2O_2} (CH_3)_2C=O + CH_3COOH$.Thus,the products are Acetone and Ethanoic acid.

For the given reaction sequence,identify the products $(C)$ and $(D)$ formed after ozonolysis of the major product $(B)$:
$(CH_3)_2CH-CHCl-CH_3$ $\xrightarrow{C_2H_5ONa / C_2H_5OH} B$ $\xrightarrow{O_3 / H_2O_2} C + D$

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For the given reaction sequence,identify the products $(C)$ and $(D)$ formed after ozonolysis of the major product $(B)$:$(CH_3)_2CH-CHCl-CH_3$ $\xrightarrow{C_2H_5ONa / C_2H_5OH} B$ $\xrightarrow{O_3 / H_2O_2} C + D$