S-O bond length is maximum in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Bond length is inversely proportional to bond order. Calculating the bond order for each species: $SO_2$: Bond order = $1.5$ $SO_3$: Bond order =

Vedclass · Accepted Answer

$SO_3^{2-}$

Vedclass · Answer

(D) Bond length is inversely proportional to bond order. Calculating the bond order for each species: $SO_2$: Bond order = $1.5$ $SO_3$: Bond order = $1.33$ $SO_4^{2-}$: Bond order = $1.5$ $SO_3^{2-}$: Bond order = $1.33$ However,considering the resonance and the number of lone pairs,the $S-O$ bond length is maximum in $SO_3^{2-}$ due to the presence of a lone pair on the sulfur atom which increases repulsion and decreases the bond order effectively compared to $SO_3$.

$S-O$ bond length is maximum in

Similar Questions

The incorrect statement regarding $O(SiH_3)_2$ and $OCl_2$ molecules is/are:

Which of the following is the correct increasing order of $O-O$ bond length in $O_2$,$O_3$,and $H_2O_2$?

Identify the correct sequence of increasing number of $\pi$-bonds in the structure of the following molecules:
$(I) \ H_2S_2O_6 \ \ \ \ \ \ \ \ \ (II) \ H_2S_2O_3 \ \ \ \ \ \ \ \ \ (III) \ H_2S_2O_5$

In the $Al_2Cl_6$ dimer,which of the following statements is true regarding the $Al-Cl$ bonds?

The shapes of $BCl_3, PCl_3$ and $ICl_3$ molecules are all

Vedclass Test Series

Exam Paper Generator

Online Exam Module