What will be the product $(A)$ in the following reaction?
$p$-cresol $\xrightarrow[(ii) H^+]{(i) CHCl_3/KOH} (A)$

The major product of the following reaction is:

The correct acidity order of phenol $(I)$,$4-$hydroxybenzaldehyde $(II)$ and $3-$hydroxybenzaldehyde $(III)$ is:

When phenol is treated with bromine water,the white precipitate formed is

Given below are two statements:
Statement $I$: Bromination of phenol in solvent with low polarity such as $CHCl_3$ or $CS_2$ requires Lewis acid catalyst.
Statement $II$: The Lewis acid catalyst polarises the bromine to generate $Br^{+}$.
In the light of the above statements,choose the correct answer from the options given below:

Consider the following reaction:
$Phenol$ $\xrightarrow{Zn\,dust} X$ $\xrightarrow[{Anhyd.\,AlCl_3}]{CH_3Cl} Y$ $\xrightarrow{Alkaline\,KMnO_4} Z$
The product $Z$ is: