D-(+)-glucose reacts with hydroxylamine (NH_2 | vedclass

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Question

(D) $D-(+)$-glucose contains an aldehyde group $(-CHO)$ at $C1$. When it reacts with hydroxylamine $(NH_2OH)$,the aldehyde group is converted into an

Vedclass · Accepted Answer

$CH=NOH-CH(OH)-CH(OH)-CH(OH)-CH(OH)-CH_2OH$

Vedclass · Answer

(D) $D-(+)$-glucose contains an aldehyde group $(-CHO)$ at $C1$. When it reacts with hydroxylamine $(NH_2OH)$,the aldehyde group is converted into an oxime group $(-CH=NOH)$. The configuration of the remaining chiral centers ($C2$ to $C5$) remains the same as in $D$-glucose. In the Fischer projection of $D$-glucose,the $-OH$ groups are at $C2$ (right),$C3$ (left),$C4$ (right),and $C5$ (right). Option $(d)$ correctly represents the structure of glucose oxime where the aldehyde carbon is transformed into the oxime functional group while maintaining the stereochemistry of the chiral carbons.

$D-(+)$-glucose reacts with hydroxylamine $(NH_2OH)$ to yield an oxime. The structure of the oxime is:

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