$2\,kg$ of metal at $100\,^oC$ is cooled by $1\,kg$ of water at $0\,^oC$ . If specific heat capacity of metal is $\frac {1}{2}$ of specific heat capacity of water, final temperature of mixture would be
$2\,kg$ of metal at $100\,^oC$ is cooled by $1\,kg$ of water at $0\,^oC$ . If specific heat capacity of metal is $\frac {1}{2}$ of specific heat capacity of water, final temperature of mixture would be
- A
$50\,^oC$
- B
More than $50\,^oC$
- C
Less than $50\,^oC$
- D
None of the above
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