$CH_3-Br + NaO-C(CH_3)_3 \to ?$

  • A
    $CH_3-O-C(CH_3)_3$
  • B
    $CH_2=C(CH_3)_2$
  • C
    $CH_2=CH_2$
  • D
    $CH_3-O-CH(CH_3)_2$

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