$0.1 \ M$ $CH_3COOH$ is titrated against $0.1 \ M$ $NaOH$. What would be the difference in $pH$ between $1/4$ and $3/4$ stages of neutralization of the acid?

  • A
    $2 \log \frac{3}{4}$
  • B
    $2 \log \frac{1}{4}$
  • C
    $2 \log \frac{8}{3}$
  • D
    $2 \log 3$

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