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(A) At standard temperature and pressure $(STP)$,$22.4 \ L$ of any gas corresponds to $1 \ mole$ of the gas.Given that $2.24 \ L$ of the gas has a mas

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Carbon dioxide

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(A) At standard temperature and pressure $(STP)$,$22.4 \ L$ of any gas corresponds to $1 \ mole$ of the gas.Given that $2.24 \ L$ of the gas has a mass of $4.4 \ g$.Therefore,the mass of $22.4 \ L$ (which is $1 \ mole$) of the gas is calculated as:$	ext{Molar mass} = \frac{4.4 \ g}{2.24 \ L} 	imes 22.4 \ L/mol = 44 \ g/mol$.The molar mass of $CO_2$ is $12 + (2 	imes 16) = 44 \ g/mol$.Thus,the gas is $CO_2$.

$4.4 \ g$ of an unknown gas occupies $2.24 \ L$ of volume at standard temperature and pressure. The gas may be

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